[plt-scheme] questions about graphical debugger

[Skeptic .]

Hi,

Two questions about the graphical debugger :
If I debug this procedure :
(define test  (¦Ë (n)                     (cond  [(> n 3) 'x]                               [(= n 3) 'y]                               [(< n 3) 'z])))
(test 1)
1- Why the step cursor goes on 'x and 'y after showing both results to be #f.
2- Why when the step cursor is at the end, the result shown is (test 1) => #<void> and not 'z ?
Thanks.
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