On Mar 22, Doug Orleans wrote:
>
> The thing that seems like voodoo to me in my version is that there's
> no mutation involved: [...]
But there is state -- in the for loop (whether one that gets mutated
or with a named let loop)...
--
((lambda (x) (x x)) (lambda (x) (x x))) Eli Barzilay:
http://www.barzilay.org/ Maze is Life!